2x^2+4(2x+7)=3(2x+4)

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Solution for 2x^2+4(2x+7)=3(2x+4) equation: 



2x^2+4(2x+7)=3(2x+4)

We move all terms to the left:

2x^2+4(2x+7)-(3(2x+4))=0

We multiply parentheses

2x^2+8x-(3(2x+4))+28=0



We calculate terms in parentheses: -(3(2x+4)), so:

3(2x+4)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

2x^2+8x-6x-12+28=0

We add all the numbers together, and all the variables

2x^2+2x+16=0

a = 2; b = 2; c = +16;
Δ = b2-4ac
Δ = 22-4·2·16
Δ = -124
Delta is less than zero, so there is no solution for the equation

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